DJC
Member
YES ....just been tied up ...sometime this week and ill
take shots of mississauga from grimsbyAre you still planning to do this?
take shots of mississauga from grimsbyAre you still planning to do this?
When people talk about 'curvature' they're generally talking about the curve between you (the observer) and the horizon, or something beyond the horizon. The curve, of course, cannot be detected with the naked eye, but its effects can, such as the obscuration of the lower parts of distant buildings and ships.
The 'left to right' curve is something different, and cannot be seen until you're way up there. At least 60,000 feet, and more like 100,000 feet for it to be significantly pronounced.
To demonstrate:
The line ab is the horizon. The observer is at o. The object you're looking at is at v.
When people talk about curvature, and use the curvature calculator, it's the line ov that they're measuring: the "straight ahead" curve.
Determining the curvature for the horizon - for ab - is an altogether different calculation, as outlined above.
For "viewer height in feet" just put in the difference between the viewer and the lake (ie, the elevation of the horizon).
Yep, that's right. Will be interesting to see how much of the SkyDome you can see, and how it compares to this photo:
He's viewing it from what looks like a building over Mountain Face park (which he says in the video), which would be well over 600 feet.
With some triangulation, he's about here.
And no curvature of the horizon is visible below 60,000.
ie H(c) = 8" x D^2 (mls),
8" x 40mls x 40mls = 12,800 ft / 12" = 1,070 Feet or 325m (approx)
so at 40mls away, the curve should hide // 1,070 Feet or approx 325m of the CN Tower,
Ok good .... we're all on the same page ....
Why is that?
I'm not being facetious,
but according to Rowbotham Experiment No 7,
Example Here: http://www.sacred-texts.com/earth/za/za12.htm
You should quite clearly be able to detect a curve?
Ditto to Mick's answer.Hi Guys,
Tell you what I find interesting about the above GIF image,
I measured Olcott to Toronto on Google Maps, 65km or 40mls
Now according to curvature maths,
ie H(c) = 8" x D^2 (mls),
8" x 40mls x 40mls = 12,800 ft / 12" = 1,070 Feet or 325m (approx)
so at 40mls away, the curve should hide // 1,070 Feet or approx 325m of the CN Tower,
Ok good .... we're all on the same page ....
Now what I find surprising,
Is that the First Bank Tower (second highest building) after the CN Tower is (according to Wiki) 290m tall minus spires,
and it is clearly visible?
In fact, strangely enough, I'd say near on a good half is clearly visible,
When, according to curvature math, it should all be under the horizon?
The curvature of the horizon (left to right) is an entirely separate thing from the curvature of the Earth. The horizon is flat.Why is that?
I'm not being facetious,
but according to Rowbotham Experiment No 7,
Example Here: http://www.sacred-texts.com/earth/za/za12.htm
You should quite clearly be able to detect a curve?
This is from Ryerson Park, Niagara-on-the-Lake, NY
How'd it go?YES ....sometime this week ill take shots of mississauga from grimsby
Did you get the shot?I ust got back from the beach ..there is zero visible today i can walk to the water and sit on a rock so ill be around 4 feet from the water .....now I'm obsessed with getting the right pic so sometime over the weekend i will get down there again when its nice..
IM positive you can see all of Toronto from the beach i could see to Mississauga to the left right to the ground . its about half way but my phone took nothing you could recognize ...
i will get the shot and we will see ...
For some people, alas, their religious vows preclude them from coming too close to evidence that clashes with their beliefs. Don't understand it meself but one must have respect for these things.I read this with great anticipation that the OP would produce a photo or two. Quite a disappointment it never materialized.
Same here.I read this with great anticipation that the OP would produce a photo or two. Quite a disappointment it never materialized.