#### Kriss3d

##### New Member

My question is this. When claimed that according to the curvature charts and the various calculations ( 8 inch per mile squared) there will be something like "this distance shouldhave x feet of curvature where is it?".

I think i might not actually know what the "drop" is defined as ?

As I understand it, if you stand on earth 6 feet above sea level and look straight ahead - a line tangent to earth, and you look at something say 10 miles away. Wouldnt the drop be what is hidden beneath the bulge ? Or is the drop defined as the bulge itself ? (though this im pretty sure is NOT right as the bulge doesnt have to be very high.)

When people say something is x miles away. Wouldnt that normally be the distance along the curve then ? Then it should be possible to take the miles as the distance and calculate how much should be hidden ?

Most curvature calculators would take the distance as the straight line from your POV to the top of whatever youre looking at but the distances used by people would be the distance along the curve thus this distance would be longer as i understand it right ?

Basically im looking for how to take the poor measurements of the flat earthes which would be distance along the curvature and apply that to calculate how much should be hidden.

It doesnt seem to me that the curvature calculators i can find does this. So do any of you people know a formula i could use for this ?